Hi Mike,

Thanks for the answer, but I can't get it to work.  Here are some specifics:

The URL I have is the public URL that a person gets when they click the 
"Share" button in Picasa Web.  Specifically, here is a real-life example:

https://picasaweb.google.com/110918005189118533839/AmericanCanyonSeptember152012?authuser=0&authkey=Gv1sRgCLTGtYSlv8jAdg&feat=directlink


I've used "110918005189118533839" as the album ID and plugged it into the 
link text you provided:

http://picasaweb.google.com/data/entry/api/user/default/albumid/[ALBUM_ID]?prettyprint=true


becomes

 http://picasaweb.google.com/data/entry/api/user/default/albumid/
110918005189118533839?prettyprint=true<http://picasaweb.google.com/data/entry/api/user/default/albumid/%5BALBUM_ID%5D?prettyprint=true>


and all I get is this message:

"Invalid entity id: 110918005189118533839"


I've tried every other value in the original URL and get the same results.

Thanks,

TJ


On Monday, December 10, 2012 2:47:24 PM UTC-8, Mike Erickson wrote:
>
> Hello TJ,
>
> Indeed, there is a way! If you request the photo entry, it will have a 
> list of media elements on it that point to the cover for that photo. 
>
> So, if you have the album ID, you can:
>
>
> http://picasaweb.google.com/data/entry/api/user/default/albumid/[ALBUM_ID]?prettyprint=true
>
> Which will contain a media:group with media:content and some 
> media:thumbnail elements, depending on the image size 
> parameters<https://developers.google.com/picasa-web/docs/2.0/reference#Parameters>you
>  passed in your request.
>
> Don't have the album ID because you're scraping the web UI? We can help 
> you with that, too! Just take the album name from the page URL (
> https://picasaweb.google.com/userid/[THISONE]) and add it to this 
> slightly modified album entry URL:
>
>
> http://picasaweb.google.com/data/entry/api/user/default/album/[ALBUM_TITLE]?prettyprint=true
>
> I hope that helps, and stop scraping the web UI. Just use the API. It's 
> okay.
>
> Thanks,
> -Mike
>
>
>

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