Hello Markus, I have tried to iimplement the example in my way. The code is as follows
import os import sys import core as grass def main(): input_map = options['H:/Shared_data/test1.tif'] output_map = options['Test_24'] ret = grass.run_command("r.in.gdal", input = input_map, output = output_map) sys.exit(ret) if __name__ == "__main__": options, flags = grass.parser() main() But I get the following error, I cant make out where I am going wrong. I have set all the Env variables as suggested in the wiki page. Please help me to implement it. F:\GRASS-6-SVN\etc\python\grass\script>python test.py Traceback (most recent call last): File "test.py", line 18, in <module> options, flags = grass.parser() File "F:\GRASS-6-SVN\etc\python\grass\script\core.py", line 359, in parser os.execvp("g.parser.exe", [name] + argv) File "F:\Quantum GIS\python\os.py", line 353, in execvp _execvpe(file, args) File "F:\Quantum GIS\python\os.py", line 389, in _execvpe func(fullname, *argrest) OSError: [Errno 22] Invalid argument With Regards Bishwarup On Wed, Mar 24, 2010 at 2:24 AM, Markus Neteler <nete...@osgeo.org> wrote: > On Mon, Mar 22, 2010 at 1:28 PM, Bishwarup Banerjee > <bishwarup.baner...@gmail.com> wrote: > > Hi All, > > > > I want to call the grass functionalities from inside my python plugins, > in > > QGIS > > For example: the Grass's raster to polygon script, with out going inside > the > > grass plugin. > > Can I set the Grass Mapset, and location from inside my python plugin? > > Is this possible? > > I think yes. See also > http://grass.osgeo.org/wiki/GRASS_and_Python > > (@all: please extend the Wiki page!) > > > my configurations are: > > QGIS 0.11, GRASS 6.3, python 2.5, Windows > > Note that there are substantial improvements in GRASS 6.4+ for Python. > > Markus >
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