Bishwarup Banerjee wrote: > I have tried to iimplement the example in my way. The code is as follows
> import core as grass This should be: import grass.script as grass or: import grass.script.core as grass > def main(): > input_map = options['H:/Shared_data/test1.tif'] > output_map = options['Test_24'] This is bogus. The keys in the "options" dictionary are the names of the options defined in the g.parser comments (assuming that you have them; if you don't, grass.parser() won't work). > But I get the following error, I cant make out where I am going wrong. I > have set all the Env variables as suggested in the wiki page. Please help me > to implement it. > > > F:\GRASS-6-SVN\etc\python\grass\script>python test.py > Traceback (most recent call last): > File "test.py", line 18, in <module> > options, flags = grass.parser() > File "F:\GRASS-6-SVN\etc\python\grass\script\core.py", line 359, in parser > os.execvp("g.parser.exe", [name] + argv) > File "F:\Quantum GIS\python\os.py", line 353, in execvp > _execvpe(file, args) > File "F:\Quantum GIS\python\os.py", line 389, in _execvpe > func(fullname, *argrest) > OSError: [Errno 22] Invalid argument I have no idea what's causing this. I suggest modifying the parser() function to print the arguments which are being passed to os.execvp(): > File "F:\GRASS-6-SVN\etc\python\grass\script\core.py", line 359, in parser > os.execvp("g.parser.exe", [name] + argv) -- Glynn Clements <gl...@gclements.plus.com> _______________________________________________ grass-dev mailing list grass-dev@lists.osgeo.org http://lists.osgeo.org/mailman/listinfo/grass-dev