Franks, you're looking at the wrong component. It's called 'bounds' and it's grouped under 'interval'. It creates an interval that you can decompose into individual numbers using the 'interval components' component.
On May 6, 11:54 am, frankS <[email protected]> wrote: > concerning find min/max of a list: > andrew: thanks, works, didn't try sorting before... > marc: thanks, didn't manage to setup it up the way you described it. > the min and and max comp are described with "find the lowest of °two° > numbers" providing A and B as input. hooking up a list to either A or > B or both doesn't return single mi/max value. what am i comparing the > list to? would you be so kind and point me to the correct setup. > frank > > On May 6, 11:28 am, frankS <[email protected]> wrote: > > > Ok, thanks for the suggestions concerning midpoint.I sometimes used > > "divide: into 2 segments" than pick the 2nd list item. But since we > > were talking about weird workarounds there might be the need for a > > dedicated component. i could construct the center of an arc/circle > > with a workaround, but i like using the center component... > > > I will move the shift tree question to a new thread. > > Sorry for messing up this one. > > > On May 6, 9:48 am, visose <[email protected]> wrote: > > > > The middle parameter might not always correspond to the mid point of a > > > curve. It's better to use the 'evaluate length' with the length as 0.5 > > > and the boolean input set as true. > > > > On May 6, 9:37 am, Rchitekt <[email protected]> wrote: > > > > > Frank, > > > > The midpoint can be found using the Evaluate Curve component. Just > > > > use 0.5 for the t-value and make sure you set your curve to > > > > reparametrize. That should do it. > > > > -Andy > > > > > On May 5, 11:05 am, Marc Syp <[email protected]> wrote: > > > > > > No need for all that. In Scalar components, there is a Min-Max node. > > > > > Hook it up to your list and then extract the interval and voila, you > > > > > have both min and max values to play with. > > > > > > Marc > > > > > > On May 5, 7:42 pm, Andrew Heumann <[email protected]> wrote: > > > > > > > @frankS > > > > > > > I get around this without scripting by: > > > > > > > 1. sorting the list, and taking the item at index=0 for the min > > > > > > 2. reversing the sorted list and taking the item at index=0 for the > > > > > > max > > > > > > > On May 5, 12:37 pm, frankS <[email protected]> wrote: > > > > > > > > 1.1.) find min/max of all list values. > > > > > > > > i don't know if there is a smart way to find the lowest or highest > > > > > > > value in a list. > > > > > > > i use a vb-component (called "list mapper") friendly shared by > > > > > > > someone > > > > > > > on this forum. > > > > > > > > frank
