visose: allright, works, thanks a lot. there are some section of the ribbons that are a bit out of my focus. also "bounds" is not listed in the some-how-associative auto-complete widget when typing "min". is the auto-complete searching the help files? maybe more tagging could help finding stuff easier...
On May 6, 12:10 pm, visose <[email protected]> wrote: > Franks, you're looking at the wrong component. It's called 'bounds' > and it's grouped under 'interval'. It creates an interval that you can > decompose into individual numbers using the 'interval components' > component. > > On May 6, 11:54 am, frankS <[email protected]> wrote: > > > > > concerning find min/max of a list: > > andrew: thanks, works, didn't try sorting before... > > marc: thanks, didn't manage to setup it up the way you described it. > > the min and and max comp are described with "find the lowest of °two° > > numbers" providing A and B as input. hooking up a list to either A or > > B or both doesn't return single mi/max value. what am i comparing the > > list to? would you be so kind and point me to the correct setup. > > frank > > > On May 6, 11:28 am, frankS <[email protected]> wrote: > > > > Ok, thanks for the suggestions concerning midpoint.I sometimes used > > > "divide: into 2 segments" than pick the 2nd list item. But since we > > > were talking about weird workarounds there might be the need for a > > > dedicated component. i could construct the center of an arc/circle > > > with a workaround, but i like using the center component... > > > > I will move the shift tree question to a new thread. > > > Sorry for messing up this one. > > > > On May 6, 9:48 am, visose <[email protected]> wrote: > > > > > The middle parameter might not always correspond to the mid point of a > > > > curve. It's better to use the 'evaluate length' with the length as 0.5 > > > > and the boolean input set as true. > > > > > On May 6, 9:37 am, Rchitekt <[email protected]> wrote: > > > > > > Frank, > > > > > The midpoint can be found using the Evaluate Curve component. Just > > > > > use 0.5 for the t-value and make sure you set your curve to > > > > > reparametrize. That should do it. > > > > > -Andy > > > > > > On May 5, 11:05 am, Marc Syp <[email protected]> wrote: > > > > > > > No need for all that. In Scalar components, there is a Min-Max > > > > > > node. > > > > > > Hook it up to your list and then extract the interval and voila, you > > > > > > have both min and max values to play with. > > > > > > > Marc > > > > > > > On May 5, 7:42 pm, Andrew Heumann <[email protected]> wrote: > > > > > > > > @frankS > > > > > > > > I get around this without scripting by: > > > > > > > > 1. sorting the list, and taking the item at index=0 for the min > > > > > > > 2. reversing the sorted list and taking the item at index=0 for > > > > > > > the > > > > > > > max > > > > > > > > On May 5, 12:37 pm, frankS <[email protected]> wrote: > > > > > > > > > 1.1.) find min/max of all list values. > > > > > > > > > i don't know if there is a smart way to find the lowest or > > > > > > > > highest > > > > > > > > value in a list. > > > > > > > > i use a vb-component (called "list mapper") friendly shared by > > > > > > > > someone > > > > > > > > on this forum. > > > > > > > > > frank
