Brian Hulley wrote:
(==) (Add xs) (Add ys) = and (map (\(x, y) -> x==y) (zip xs ys))
What on earth was I thinking!!! ;-) Should be: (==) (Add xs) (Add ys) = xs == ys (Doesn't affect the validity of my argument though...) _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe