Il Sat, Aug 26, 2006 at 01:27:38AM +0200, Daniel Fischer ebbe a scrivere: > Because T a is a function type, namely Int -> (a,Int), so ...
> iHowever, neither T1 a nor T2 a is a function type, a value of type > T1 a is a function _wrapped by the data (or value) constructor T1_ (the same > applies to T2, of course), so before you can apply mkT1 a to an Int, you have > to unwrap it: so, if I understand correctly, mkT is just a partial application *becase* of its "fake" type signature... that's a bit confusing... also because that "type" cannot be instance of a class. moreover why it is possible to declare something like this? data T2 a = T2 (Int -> (a,Int)) is there any usefulness? I hoped it could work as with types declared with "type". perhaps this is silly, but it is not possible to declare function types? could you please indicate me some documentation that explains this kind of stuff? So far I didn't find anything on that. Thank you. Andrea _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
