Magnus Jonsson wrote: [...] > but your example fails on infinite lists [...] > take 2 $ snd $ head $ splitStreams (map (\x -> (0 ,x)) [1..])
Any approach, even sieving, will struggle with infinite lists, won't it? (take 2 . snd . head . splitStreams) [(i, i) | i <- [0..]] Regards, Tom _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe