How about this, infiniteRS :: [Int] infiniteRS = let acum a1 a2 = a2 ++ acum (a1++a2) a1 in 1 : acum [1] [0]
it certainly fits in one line but it's not really elegant _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
