> Is there a simple way to do this, i.e. using existing libraries? Yes indeed. I'll be traveling over the next two days, and am shooting for a fully functional hackage release by mid next week.
> What I need is a Haskell expression parser which outputs values of type > Language.Haskell.TH.Syntax.QExp, but I can't see one available in the TH > libraries, or in the haskell-src(-exts) libraries. My strategy is to use the existing haskell-src-exts parser, then translate that AST to the TH AST. Once I've got settled in one place, I'll follow up with a brain dump :) > Cheers, > Reiner Matt _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
