It sounds like you're doing exactly what I'm looking for. I look forward to more.
Reiner On Tue, Oct 21, 2008 at 4:28 PM, Matt Morrow <[EMAIL PROTECTED]> wrote: > > Is there a simple way to do this, i.e. using existing libraries? > > Yes indeed. I'll be traveling over the next two days, and am shooting > for a fully functional hackage release by mid next week. > > > What I need is a Haskell expression parser which outputs values of type > > Language.Haskell.TH.Syntax.QExp, but I can't see one available in the TH > > libraries, or in the haskell-src(-exts) libraries. > > My strategy is to use the existing haskell-src-exts parser, then > translate that AST to the TH AST. > > Once I've got settled in one place, I'll follow up with a brain dump :) > > > Cheers, > > Reiner > > Matt > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe >
_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe