In this case you have to use parens -- two dollar signs, like this
B.intercalate $ B.intercalate ByteString [ByteString] $ [ByteString]
would also not type check -- it is exactly equivalent to your first
example:
B.intercalate (B.intercalate ByteString [ByteString] ([ByteString]))
just with one level of extra parentheses.
If for some reason you absolutely need to avoid parentheses (mostly as
a thought exercise, I guess), you'd have to have a flipped version of
intercalate:
flippedIntercalate :: [ByteString] -> ByteString -> ByteString
flippedIntercalate = flip B.intercalate
flippedIntercalate [ByteString] $ B.intercalate ByteString [ByteString]
of course, this is pretty contrived.
-Ross
On Jan 5, 2009, at 1:23 PM, Galchin, Vasili wrote:
yep ... that is exactly what I meant!! so can I use more $'s or must
I use parens (as you did) to disambiguate?
Vasili
On Mon, Jan 5, 2009 at 12:18 PM, Ross Mellgren <rmm-
hask...@z.odi.ac> wrote:
Did you mean:
B.intercalate (B.intercalate ByteString [ByteString]) [ByteString]
($) applies all the way to the right, so you were giving the inner
intercalate two lists of ByteString.
-Ross
On Jan 5, 2009, at 1:17 PM, Galchin, Vasili wrote:
Hi Max,
That is what should happen .... The inner B.intercalate will
produce the ByteString to be used by the B.intercalate. ??
Vasili
On Mon, Jan 5, 2009 at 12:13 PM, Max Rabkin <max.rab...@gmail.com>
wrote:
2009/1/5 Galchin, Vasili <vigalc...@gmail.com>:
> Hello,
>
> I have the following:
>
> B.intercalate $ B.intercalate
> ByteString
> [ByteString]
> [ByteString]
>
> I get a type error with this. If I comment out the 2nd
B.intercalate
> and the third parameter I get no type errors.
B.intercalate needs a ByteString and a list of ByteStrings. Two
B.intercalates need two ByteStrings and two lists of ByteStrings.
--Max
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