Hi,
you could do something like
> instance (Show a,Read a) => Binary a where
> put = put . show
> get = fmap read get
But then you will need the following language extensions:
FlexibleInstances, OverlappingInstances, UndecidableInstances
I don't know how safe this is but it seems to work.
Regards,
Martin.
Svein Ove Aas schrieb:
I'm in the process of writing a distributed filesystem (in haskell,
yay), which of course means I'm using Binary for de/serialization.
Now, that's fine enough, but for simplicity (and for wireshark), I'd
like to be able to have Binary fall back on an instance based on
Show/Read for any type that lacks any other Binary instance..
Well, I understand why this would be somewhere between extremely hard
and impossible in haskell '98, but I'm not entirely up on all the
extensions, so I thought I'd ask - given every extension implemented
in ghc 6.10.1, is there any reasonable way to do this?
_______________________________________________
Haskell-Cafe mailing list
[email protected]
http://www.haskell.org/mailman/listinfo/haskell-cafe
_______________________________________________
Haskell-Cafe mailing list
[email protected]
http://www.haskell.org/mailman/listinfo/haskell-cafe
