A... should be split into "A.." and "."
As I read the (on-line) report the "maximal munch" rule says that you should read the longest lexeme. It does not say that two operators have to be separated by whitespace.
Because A... is not a lexeme, the longest lexeme you can read from "A..." is "A.." (qualified dot-operator).
Arthur
On maandag, sep 15, 2003, at 12:11 Europe/Amsterdam, Malcolm Wallace wrote:
Marcin 'Qrczak' Kowalczyk <[EMAIL PROTECTED]> writes:
Argh, I was wrong. It's A.. (qualified operator), then . (operator).
You are forgetting about the maximal munch rule. An operator cannot appear
directly next to another operator without some whitespace to separate them.
For instance "A.+." is an operator called (+.) from module A, not an
operator called + followed by compose.
But, although "A...." could be the three-dot operator "..." from the module A, it is not possible to have "A..." interpreted as a two-dot operator, because ".." is reserved as sugar for enumeration sequences, and so is explicitly excluded from the varsym production.
Thus, the only possible lexical interpretation is the one you first suggested, namely a constructor "A" followed by a three-dot operator "...".
Regards, Malcolm _______________________________________________ Haskell mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell
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