>bool_expr : '!' bool_expr > | num_expr '=' num_expr > | 'b' > ; > >num_expr : bool_expr > | 'n' > ;
Yes, this is ambiguous. If your input is "!b=n", it can't tell which of these you mean: ! ( b = n ) (!b) = n R's, John _______________________________________________ [email protected] https://lists.gnu.org/mailman/listinfo/help-bison
