Thanks John! One question though: why do the precedence levels of operators '!' and '=' defined at the beginning of my grammar don't apply in this case? Moreover, I thought that ambiguous associativity was more likely to create shift/reduce conflicts rather than reduce/reduce conflicts, wasn't it?
Regards, Florent Le 19/11/2013 00:17, John Levine a écrit : >> bool_expr : '!' bool_expr >> | num_expr '=' num_expr >> | 'b' >> ; >> >> num_expr : bool_expr >> | 'n' >> ; > > Yes, this is ambiguous. > > If your input is "!b=n", it can't tell which of these you mean: > > ! ( b = n ) > > (!b) = n > > R's, > John > _______________________________________________ help-bison@gnu.org https://lists.gnu.org/mailman/listinfo/help-bison
