We finally took some steps to attack this problem on the processor that 
showed the highest I/O retry count. 

- During the week, the CE removed all unused ESCON cards on one processor. 
(Nondisruptive)
- On the monthly IPL weekend, we brought down all LPARs on the processor.
- We did two PORs: first with the previous IOCDS, then with the current 
IOCDS.

The double POR was advised by the CE in order to force redistribution of 
the SAPs across remaining chpids. Otherwise a minimal POR with the same 
IOCDS would not necessarily reassign SAPs. 

The result is heartening but a trifle puzzling. RMF still reports 
unbalanced SAP usage, with one being used conspicuously less than the 
others. But the real problem--excessive I/O retries--appears to be fixed. 
The count is not zero but far lower than it was before the exercise. 

.
.
JO.Skip Robinson
Southern California Edison Company
SHARE MVS Program Co-Manager
626-302-7535 Office
323-715-0595 Mobile
[EMAIL PROTECTED]

IBM Mainframe Discussion List <IBM-MAIN@BAMA.UA.EDU> wrote on 03/01/2006 
09:38:28 AM:

> We're getting reports from RMF of excessively high I/O retries on some 
> systems. In one case, we've seen the number of retries go higher than 
the 
> actual number of I/Os!
> 
> Assuming that the numbers are being reported correctly, does anyone have 
a 
> notion of what might cause this anomaly? Some facts:
> 
> - Reports do not detail the I/Os being retried by channel or device; 
just 
> a total number
> - No channel looks excessively busy according to RMF
> - We see this on more than one CEC (all z900)
> - SAP/IOP processors are 'unbalanced'
> 
> This last point might be an issue. We have a fairly large number of now 
> unused ESCON channels whose function has moved over to FICON. It appears 

> that the three SAPs divide up all channels among themselves, but one of 
> them--which happens to have the most idle channels--is less than half as 

> busy as the other two. Maybe we need to physically remove the unused 
> channels in order to redistribute the SAPs more evenly across the active 

> channels.


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