On Tue, 12 Jan 2021 19:19:01 +0200, Itschak Mugzach wrote: > >So if I ignore leap seconds, Can I just divide the number by 409600 and > 4096000000?
>subtruct 1.1.1970-1.1.1900? > Are you doing it the hard way? Borrowing from seconds to minutes, minutes to hours, hours to days, days to months (which aren't of uniform lengths), months to years (which aren't of uniform lengths in some calendars) ...? Show sample data and your code. -- gil ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
