On 3/14/2013 7:10 AM, Elardus Engelbrecht wrote:
John McKown wrote:
What I do is use REXX. A UNIX REXX shell script is rather easy:
Agreed. REXX can do things an achieve results in one single command line. Use
the pipe thing to send and receive keywords/parms to different commands.
/* rexx */
today=date('b') /* today's date in base form */
yesterday = today - 1
say date('s',yesterday,'b') /* yesterday in yyyymmdd form */
Will above takes Leap Year in account? I have a version of that example, but
must receive Julian dates from a product and gives Julian date back, taking
Leap Year in account.
For example, if today is 2012/03/01, it must accept it as 12061 and gives back
12060 for 2012/02/29.
And 2013/03/01 must be accepted as 13060 and gives back 13059 as yesterday.
Just something for you to think about...
Groete / Greetings
Elardus Engelbrecht
If you're coding in C, Assembler, COBOL, or PL/I, you can use
the Language Environment date functions, which can do what
you want pretty simply.
call CEELOCT to get today's date in Lilian format
subtract 1
call CEEDATE to convert to a formatted date in a wide
variety of options
this does account for leap years and such.
It's not a shell command, but you could write a very
short program that returns the output from the CEEDATE
call and then just invoke the program from a shell
script.
--
Kind regards,
-Steve Comstock
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