I forgot the SETA, of course:

           LCLA  &FOOCNT
&FOOCNT    SETA  10
FOO        DS    &FOOCNT.CL5


Am 31.03.2024 um 11:31 schrieb Bernd Oppolzer:
I don't know the answer to your question. Don't know, if such an attribute exists or if the repetition count is really stored as an attribute of the symbol. But:

FOO        DS    10CL5
ENDFOO     EQU   *
COUNTFOO   EQU   (ENDFOO-FOO)/L'FOO

This way you can compute the count and put it into a symbol.

Another approach would be not to use constant repetition counts, but macro symbols from the start, like

            LCLA  &FOOCNT
FOO        DS    &FOOCNT.CL5

HTH, kind regards

Bernd



Am 31.03.2024 um 10:53 schrieb Binyamin Dissen:
Given

            FOO   DS   10CL5

which attribute / macro function extracts the repetition count - 10

I assume that it must exist but I am not finding it.

--
Binyamin Dissen <bdis...@dissensoftware.com>
http://www.dissensoftware.com

Director, Dissen Software, Bar & Grill - Israel

----------------------------------------------------------------------
For IBM-MAIN subscribe / signoff / archive access instructions,
send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN

----------------------------------------------------------------------
For IBM-MAIN subscribe / signoff / archive access instructions,
send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN

Reply via email to