So the statement

originalsize="5085091600"  or 5,085,091,600 bytes.

That is probably how big the file should be.  However I would make it larger.

What is the current size?


Lizette


> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On
> Behalf Of Mainframe Mainframe
> Sent: Tuesday, December 09, 2014 7:08 AM
> To: IBM-MAIN@LISTSERV.UA.EDU
> Subject: Re: RSU UNZIP space issue.
> 
> Hello Kurt,
>                   Thanks for response. I just checked this 
> /u/SLE/RSU1410/GIMPAF.XML
> file and found below entry.
> 
> <ARCHDEF
> name="SMPPTFIN/S0001.SHOPZ.S2654303.SMPMCS.pax.Z"
> type="SMPPTFIN"
> originalsize="5085091600"
> size="2760339456"
> hash="1C69AA496915DB08EF19DBC53C0A0221D6EC7D39">
> </ARCHDEF>
> 
> By looking at this, can you please suggest, what should be the size of
> /u/SLE/RSU1410/temp for SMPWKDIR DD.
> 
> 
> 
> On Tue, Dec 9, 2014 at 7:28 PM, Kurt Quackenbush <ku...@us.ibm.com> wrote:
> 
> > But my unzip still getting failed, with below error. I tried enough
> > ways by
> >> having larger size but same issue.
> >>
> >
> > The space error occurs during the unpax operation.  Therefore, the
> > directory identified on the SMPWKDIR DD statement is where you need
> > free space.  In your case that is /u/SLE/RSU1410/temp.  I suggest you
> > check out file /u/SLE/RSU1410/GIMPAF.XML and look for the <ARCHDEF>
> > statement that describes the SMPMCS file.  On that statement is an
> > originalsize attribute that identifies, in bytes, how big the
> > uncompressed original SMPMCS file is.  You will need at least this much free
> space in the SMPWKDIR directory.
> >
> > Kurt Quackenbush -- IBM, SMP/E Development
> >

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