Or "If wordpos(answer, 'Y YES') = 0 then do ..."
Regards,
Richard Schuh
________________________________
From: The IBM z/VM Operating System [mailto:[EMAIL PROTECTED] On Behalf
Of Huegel, Thomas
Sent: Monday, July 07, 2008 12:02 PM
To: IBMVM@LISTSERV.UARK.EDU
Subject: Re: REXX coding question.
It must be a slow day in Bedrock.
I was looking at this and realized that there may be a flaw.
As it is written it doesn't matter what the 'ANSWER' is as long as it
starts with a 'Y' it will be true.
A response of YABADABADOO would pass the test.
My guess is what you really want is that ONLY 'Y' and 'YES' should be
valid.
In that case take the SUBSTR(ANSWER,1,1) out and just use ANSWER..
i.e. IF ANSWER ¬= 'Y' & ANSWER ¬= 'YES' THEN
-----Original Message-----
From: The IBM z/VM Operating System [mailto:[EMAIL PROTECTED]
Behalf Of Huegel, Thomas
Sent: Monday, July 07, 2008 11:32 AM
To: IBMVM@LISTSERV.UARK.EDU
Subject: Re: REXX coding question.
Try it this way:
IF SUBSTR(ANSWER,1,1) ¬= 'Y' & ANSWER ¬= 'YES' THEN
-----Original Message-----
From: The IBM z/VM Operating System [mailto:[EMAIL
PROTECTED] Behalf Of Howard Rifkind
Sent: Monday, July 07, 2008 11:24 AM
To: IBMVM@LISTSERV.UARK.EDU
Subject: REXX coding question.
This is confusing me.
The response to the variable 'answer' is a Y.
Yet this portion of the code isn't working. Shouldn't
the logic just fall thru because the response was a Y.
IF SUBSTR(ANSWER,1,1) /= 'Y' | ANSWER /= 'YES' THEN
DO
SAY ANSWER
SAY 'THE WRONG RESPONSE HAS BEEN ENTERED'
SAY
SAY 'PROCEDURE IS TERMINATING, PLEASE TRY AGAIN'
EXIT
END
Thanks
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