On 8/31/2011 7:21 AM, Ingo Randolf wrote:
Hi all. I have a list with float-values describing an image like this: [R, G, B, A, R, G, B, A, R, G, B, A, R, G, B, A, R, G, B, A, ... etc.] the RGBA-values are from 0. - 1. is there a clever way to make a PIL-Image out of something like this? i played around with putdata... and came along with this, very, very slow solution: px = list-of-rgba-values-as-floats img = the-image #make int-tuples newdata = [(int(px[(x*4)]*255), int(px[(x*4)+1]*255), int(px[(x*4)+2]*255), int(px[(x*4)+3]*255)) for x in range( img.size[0] * img.size[1] )] Image.putdata(newdata) well i never saw a result, because it took too long for my short patience... ;) i also tried to set the values pixel-wise... this is also very, very slow... how to do that in a more clever way? thanks for any hints inx
Consider using numpy <http://numpy.scipy.org/> and Image.fromarray. For example:
import numpy from PIL import Image shape = 256, 256, 4 px = list(numpy.random.rand(shape[0]*shape[1]*shape[2])) newdata = numpy.array(px, dtype=numpy.float32) newdata *= 255.99998474 newdata = newdata.astype(numpy.uint8) newdata.shape = shape image = Image.fromarray(newdata) Christoph _______________________________________________ Image-SIG maillist - Image-SIG@python.org http://mail.python.org/mailman/listinfo/image-sig