Benas,
> On May 15, 2020, at 04:33, Benas IML <benas.molis....@gmail.com> wrote:
>
> Hey,
>
> `guard` would be a keyword this means that all of the classes, interfaces and
> traits named Guard would be illegal. Therefore Laravel's `Guard` interface
> would be incompatible with PHP 8 which in turn means thousands of web
> applications would be too.
>
> Best regards,
> Benas Seliuginas
If the parser were sufficiently smart, I don't think 'guard' would actually
conflict with a class or function named 'guard'. If the syntax were:
guard (EXPRESSION) else STATEMENT_OR_BLOCK
then, 'guard' could not conflict with a class name, because there's no existing
syntax that would fit the pattern of a type name followed by a parenthesis —
you can't call a type name as if it were a function. Even if you could, it
would still not conflict with a function call, because the 'else' keyword after
the close parenthesis would not be valid syntax immediately following a
function call.
So the main question there is, is the parser sufficiently smart to be able to
see 'guard' and look ahead for the 'else' to disambiguate a function call from
a guard statement?
-John
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