>
> Why I mean by:
> Type HINTING is not type ENFORCEMENT.
> is that:
> function foo(int $a) {}
>
> foo(1); // OK
>
> foo("1"); // OK - the string is juggled to an int when the
> function is called
> // ENFORCEMENT would have (in some interpretations)
> caused this to
> // FAIL since the function argument was a string.
>
I have not been following very closely this conversation so this might have
been answered already:
$b = '5';
function foo( int &$a )
{
echo gettype( $a );
}
foo( $b );
echo gettype( $b );
what is type of $b after the function call?
--
Mikko Koppanen
