Hi!
If I am understanding the text correctly it is saying that
$f1 = f1();
$f2 = f2($f1);
$f3 = f3($f2);
is using more memory than
$f3 = f3(f2(f1()));
Short answer: it doesn't matter, use either as you wish.
Long answer: Technically, the former also uses hash buckets to bind
values to the symbol table, so it can use more memory (and if it so
happens that using these variables makes symbol table go over hashtable
threshold, hashtable internal storage size will be increased), so it
will consume marginally more memory. But the difference is completely
negligible.
--
Stanislav Malyshev, Software Architect
SugarCRM: http://www.sugarcrm.com/
(408)454-6900 ext. 227
--
PHP Internals - PHP Runtime Development Mailing List
To unsubscribe, visit: http://www.php.net/unsub.php
