LuXugang commented on pull request #705:
URL: https://github.com/apache/lucene/pull/705#issuecomment-1049639011


   
   
   
   
   > We need two cases:
   > 
   > * Checking whether all documents match and returning values.getDocCount(). 
This works when there are no deletions.
   > * Actually counting the number of matching points. This only works when 
there are no deletions and the field is single-valued (docCount == size), plus 
we only want to apply it in the 1D case since this is the only case when we 
have the guarantee that it will actually run fast since there are at most 2 
crossing leaves.
   
   
   Thanks @jpountz, now I fully understand your thought.
   


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