Hi Vasile,
Strange that this does not work.
Did you try to isolate the problem to a minimum program without using special -
other - procedures so that it can easily be reproduced by anybody that does not
have the library you are using?
That would make it easier to find the root cause.
Thanks.
Kind regards,
Rob
________________________________
Van: jallib@googlegroups.com <jallib@googlegroups.com> namens vsurducan
<vsurdu...@gmail.com>
Verzonden: donderdag 11 november 2021 13:47
Aan: jallib@googlegroups.com <jallib@googlegroups.com>
Onderwerp: [jallib] adc average
Hi all ( aka Kiste and Rob&Rob ?) :)
One possible solution to take 8 adc average values is below (and does not work):
const sample_nr = 8 ; buffer size dimension
var word voltage1_a[sample_nr] ; sample array
var word one_ch_ad_read
var word voltage1 = 0 ; the average value we need
const word c256 = 256
var byte i
for 8 using i loop
one_ch_ad_read (0, 0b10, 0b00, 1) ; read adc procedure
ch0_adc_value = c256*ADRESH + ADRESL ; compute result
voltage1_a [i] = ch0_adc_value ; store sample
voltage1 = voltage1 + voltage1_a[i] ; do a sum of all samples each i step
end loop
voltage1 = voltage1 >> 3 ; divide by 8 and get the adc average
The issue is at the line:
voltage1 = voltage1 + voltage1_a[i] ;
initially voltage1 = 0
for i=0 voltage1 = 0 + voltage1_a[0]
for i=1 voltage1 = voltage1 (i=0) + voltage1_a[1] ...etc
this is not working as presumed...
If I remove this line from for...loop...end loop and write as:
voltage1 = voltage1_a [0] + voltage1_a [1] + voltage1_a [2] + voltage1_a [3]
+ voltage1_a [4] + voltage1_a [5] + voltage1_a [6] + voltage1_a [7]
then everything is ok.
The question is: why it does not work?
thx
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