On 11/15/05, Doug Cutting <[EMAIL PROTECTED]> wrote: > One option is to keep a score per document,
That's what I was thinking... float[maxDoc[]] scores scores[doc] += tf(term) * idf(term) * norm(term.field) It would be nice to keep score compatibility with the current BooleanQuery, then that could be transparently used when the number of terms was small. However, one problem I don't know how to solve is Weight.sumOfSquares(), which needs to know the idf of every single term, before the scorer is even created! For this reason, perhaps score compatibility can only be kept when idf is excluded (which it sounds like most people are in favor of for automatically expanding term queries anyway). -Yonik Now hiring -- http://forms.cnet.com/slink?231706 --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
