16 jul 2008 kl. 02.55 skrev John Patterson:
Karl Wettin wrote:


Or just set the boost to zero on the individual filter fields, or on
the whole filter expression.

+(my query) +(filter1 OR filter2 AND filter3)^0



That sounds perfect! I thought that boosts would be multiplied together to give 0 for the whole expression. But I never looked into it. So thanks
again.

I'll try this during the week and post my results.

After sleeping on this it hit me that you might be able to save a bit of CPU ticks by decorating queries and bypassing the scorer rather than evaluating the score and then multiply it with 0. Probably not too much though. Not much but might be worth mentioning.


          karl

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