Fun exercise - someone who knows Scala can probably do better - of
course you could hide all this away in a library and make it really
easy if you wanted:
val m = Map(1->"a",2->"b",3->"c")val field =
m(1).getClass.getDeclaredField("value")field.setAccessible(true)val
mods =
field.getClass.getDeclaredField("modifiers")mods.setAccessible(true)mods.setInt(field,
field.getModifiers & ~java.lang.reflect.Modifier.FINAL)field.set(m(1),
field.get(m(2)))println(m)// => Map(1 -> b, 2 -> b, 3 -> c)
On Fri, Nov 25, 2011 at 10:50 AM, Kevin Wright <kev.lee.wri...@gmail.com> wrote:
> C'mon!
> 1. Open a fresh scala REPL. No imports, no other lines of code, just a clean
> standard REPL
> 2. val m = Map(1->"a",2->"b",3->"c")
> 3. Your challenge, should you accept it, is to manipulate m in such a way as
> to change its value
> 3a. and no, creating a new m doesn't count
>
> 2011/11/25 Cédric Beust ♔ <ced...@beust.com>
>>
>> On Thu, Nov 24, 2011 at 3:42 PM, Kevin Wright <kev.lee.wri...@gmail.com>
>> wrote:
>>>
>>> it embraces the same ideals of immutability that he once championed
>>
>> We already went through this, Scala "the language" does very little to
>> enforce immutability. Hardly more than Java.
>> --
>> Cédric
>
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