XPath, by nature, tends to be bredth-first, which is the ordering
you're seeing because that's how I implemented it.
You're seeing them in-order for each level:
b1 b4
b2 b3 b5 b6
I guess we could hack to avoid that to always insert elements that
were found below a previously selected element, after it. (Well,
I know what I meant by that sentence, even if it's not clear to
anyone else ;) )
Probably just a migration to using iterator.add() instead of
list.add().
-bob
On Wed, 20 Mar 2002, Mark Hortman wrote:
> Here is a very simple test case.
>
> //b
>
> I would expect b1, b2, b3, b4, b5, b6
> All the other programs I have tried return that, Jaxen returns
> B1, b4, b2, b3, b5, b6
>
> <?xml version="1.0" encoding="UTF-8"?>
> <a>
> <a>
> <b id='b1'></b>
> <a>
> <b id='b2'></b>
> <b id='b3'></b>
> </a>
> </a>
> <a>
> <b id='b4'></b>
> <a>
> <b id='b5'></b>
> <b id='b6'></b>
> </a>
> </a>
> </a>
>
> -----Original Message-----
> From: James Strachan [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, March 19, 2002 10:24 AM
> To: Mark Hortman; [EMAIL PROTECTED]
> Subject: Re: [Jaxen] How to use position() function
>
> From: "Mark Hortman" <[EMAIL PROTECTED]>
> > Can someone help a xpath newbie figure out a simple xpath expression?
> >
> > Upon learning that //someelement does not guarantee the order that things
> > come back in are document order, I have switched tacts and decided to try
> to
> > handle it my self. I was thinking about playing around with the
> position()
> > function, but cannot get Jaxen to return the position of an element to me.
>
> Though generally //someelement will return things in order. Jaxen should
> walk the document tree in order matching XPath expressions so for simple
> paths like //foo it should work. Or do you have a test case where it
> doesn't?
>
> James
>
>
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