Rajarshi,
The question is:
How important is it that you load the models one at a time?
That is NOT possible in Jmol 10.9.85. There are a couple of ways around this:
1) Provided these are SDF files, a line containing just $$$$ separates
different models. So you could:
var m1 = "...";
jmolAppletLoadInline(400, m1, "spacefill on;");
var m2 = "...";
jmolLoadInline(m1 + "\n$$$$\n" + m2);
or, if you want to be a little fancier and load the second model so that
it just magically "appears" with the first model, you could use:
jmolLoadInline("save orientation;"
+"data \"model data\""
+m1+"\n$$$$\n"+m2
+" end \"model data\";"
+"frame 0;"
+"restore orientation;")
The key here is that we are loading the first model AGAIN, this time with
the second model. The data command allows you to bracket an inline load
with script on both sides. In this case, we save and restore the
orientation, and we use frame 0 to display both models.
Maybe this isn't what you had in mind, but I'm using it as an illustration
anyway.
Bob Hanson
> On Thu, 2006-10-26 at 19:38 +0200, Angel Herraez wrote:
>> Timothy Driscoll answered to Rajarshi Guha:
>>
>> > > * Since Jmol cannot show multiple structures, I need to convert my
>> SDF
>> > > to PDB and concatenate it to the protein PDB. Is this correct?
>> > >
>> > as far as I know, yes - you will need to concatenate the structures
>> > as independent MODEL (or perhaps FRAME) records.
>>
>> Wrong. Recent versions of Jmol CAN load multiple structures, so there
>> is no need to concatenate files. Don't know if different formats will
>> be trouble, but get a current prerelease version of Jmol and try.
>
> How would this be done?
>
> Currently I do:
>
> var mol1 = "...";
> jmolAppletLoadInline(400, m1, "spacefill on;");
>
> To load the next one would I do
>
> var m2 = "...";
> jmolLoadInline(m2);
>
> Or is there some other approach?
>
> -------------------------------------------------------------------
> Rajarshi Guha <[EMAIL PROTECTED]>
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> -------------------------------------------------------------------
> Every nonzero finite dimensional inner product
> space has an orthonormal basis.
> It makes sense, when you don't think about it.
>
>
>
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