right! duh..
On Thu, Feb 19, 2015 at 11:18 AM, Angel Herráez <angel.herr...@uah.es>
wrote:
> > I mean
> >
> > z < 5 AND z > -5
>
> No, that would be position along the Z axis. We need distance to the
> Z axis. i.e. perpendicular to your suggestion
>
> Transversal not axial with respect to the channel axis
>
>
>
>
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