how in the world would jQuery know if you're trying to filter on the text content "div" or on a descendant div element?
--Karl On Dec 17, 2009, at 4:35 PM, Matt Maxwell wrote: > It's a selector or a string of text. jQuery already contains the > ability to intuitively decipher its selectors. > > For example, filter can contain an expression or a function. These > are two completely different things as well. > > On Thu, Dec 17, 2009 at 3:13 PM, Karl Swedberg > <k...@englishrules.com> wrote: > But :has() and :contains() do two completely different > things. :contains() filters based on text contents while :has() > filters based on selectors. So, I think it would be a really bad > idea to try to combine them. > > --Karl > > > On Dec 17, 2009, at 3:48 PM, Matt Maxwell wrote: > >> I think .has() should return a bool, :has() should be combined >> with :contains() (the finished filter named :contains()), >> and .contains() should go away. >> >> That seems to make the most sense to me, anyways. >> >> On Thu, Dec 17, 2009 at 9:20 AM, Karl Swedberg >> <k...@englishrules.com> wrote: >> On Dec 16, 2009, at 11:14 PM, John Resig wrote: >> >>> People are use to using .has()? It was only just added - at the same >>> time as .contains() as well. >>> >>> I'll mull over the .contains() discrepancy. I may just punt it and >>> push people towards .has() anyway. >>> >>> Looking at .has() now I'm not 100% sure why it's filtering and not >>> just returning a boolean, like .is(). Hmm. If .has() returns a >>> boolean >>> then yeah, consider .contains() gone (and a jQuery.contains will be >>> provided for those that need a lightweight method). >>> >>> --John >> >> >> But if .has() returns a boolean, then we have the same problem >> with :has() vs. .has() as we had with :contains() vs. contains(). >> >> Since :has() is a filter, I would expect .has() to be a filter. >> >> On Dec 17, 2009, at 12:45 AM, Rick Waldron wrote: >>> John, I tend to assume that anything prefixed with 'is' or 'has' >>> will return a boolean. I think this is likely a common assumption. >> >> I typically assume the same thing, but in this case .has() is not a >> prefix; it's the full method name. And we already have the pseudo- >> selector :has() that acts as a filter. >> >> >> --Karl >> >>> On Wed, Dec 16, 2009 at 11:04 PM, ajpiano <ajpi...@gmail.com> wrote: >>>> It seems like a matter of course that means of filtering that are >>>> exposed as both pseudoselectors and methods on the jQuery prototype >>>> return the same set of elements, or at least that they generally >>>> apply >>>> the same principle in filtering. Examples include eq, not, first, >>>> last, and has. While the :parent pseduo doesn't work the same >>>> as .parent(), most developers know what they're looking for if >>>> they're >>>> using :parent. >>>> >>>> The new $.fn.contains method, however, doesn't work like :contains. >>>> Rather than searching for the text content of >>>> elements, .contains() is >>>> just a shortcut to $(elem).has("foo").length > 0. I'm not sure why >>>> this is really a necessary shortcut, given that most people are >>>> plenty >>>> used to doing something like .has().length anyway. I tend to >>>> think, >>>> however, that .contains () should work like :contains, for >>>> consistency's sake. >>>> >>>> This would have the added benefit of allowing those people who do >>>> use :contains to write code like this: >>>> >>>> var foo = "barbazbat"; >>>> $("div").contains(foo); >>>> >>>> instead of >>>> $("div:contains("+foo+")"); >>>> >>>> Anyone else have any thoughts on this? >>>> >>>> --adam >>>> >>>> -- >>>> >>>> You received this message because you are subscribed to the >>>> Google Groups "jQuery Development" group. >>>> To post to this group, send email to jquery-...@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> jquery-dev+unsubscr...@googlegroups.com >>>> . >>>> For more options, visit this group at >>>> http://groups.google.com/group/jquery-dev?hl=en >>>> . >>>> >>>> >>>> >>> >>> -- >>> >>> You received this message because you are subscribed to the Google >>> Groups "jQuery Development" group. >>> To post to this group, send email to jquery-...@googlegroups.com. >>> To unsubscribe from this group, send email to >>> jquery-dev+unsubscr...@googlegroups.com >>> . >>> For more options, visit this group at >>> http://groups.google.com/group/jquery-dev?hl=en >>> . >>> >>> >> >> >> -- >> >> You received this message because you are subscribed to the Google >> Groups "jQuery Development" group. >> To post to this group, send email to jquery-...@googlegroups.com. >> To unsubscribe from this group, send email to >> jquery-dev+unsubscr...@googlegroups.com >> . >> For more options, visit this group at >> http://groups.google.com/group/jquery-dev?hl=en >> . >> >> >> -- >> >> You received this message because you are subscribed to the Google >> Groups "jQuery Development" group. >> To post to this group, send email to jquery-...@googlegroups.com. >> To unsubscribe from this group, send email to >> jquery-dev+unsubscr...@googlegroups.com >> . >> For more options, visit this group at >> http://groups.google.com/group/jquery-dev?hl=en >> . > > > -- > > You received this message because you are subscribed to the Google > Groups "jQuery Development" group. > To post to this group, send email to jquery-...@googlegroups.com. > To unsubscribe from this group, send email to > jquery-dev+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/jquery-dev?hl=en > . > > > -- > > You received this message because you are subscribed to the Google > Groups "jQuery Development" group. > To post to this group, send email to jquery-...@googlegroups.com. > To unsubscribe from this group, send email to > jquery-dev+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/jquery-dev?hl=en > . -- You received this message because you are subscribed to the Google Groups "jQuery Development" group. 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