This is the code:
$(".delete").click(function(e){
var id = $(this).attr("id_delete")
$("#confirm_box").css({left: e.pageX-453, top: e.pageY})
$("#confirm_box").fadeIn(300);
$("#del_nao").click(function(){
$("#confirm_box").fadeOut(300);
$(".delete").attr("id_delete","");
});
$("#del_sim").click(function(){
alert(id);
$("#del_sim").attr("id_user",id);
$.ajax({
type: "POST",
url:"../painel/kern_usuarios.php",
data: "id="+$(this).attr("id_user")+"&acao=del_user",
success: function(msg){
if(msg)
{
$("#confirm_box").fadeOut(300)
$("#answer_box").text("Usuario deletado com
sucesso");
$("#answer_box").fadeIn(1000, function(){
$(this).animate({opacity:1.0}, 1000, "",
function(){
$(this).fadeOut(1000, function(){
$($("tr").attr("id_linha")).find("[EMAIL PROTECTED]"+id+"]").slideUp("slow");
});
});
});
}
else
{
$("#confirm_box").fadeOut(300)
$("#answer_box").text("Erro ao deletar
usuario");
$("#answer_box").fadeIn(300);
}
}
});
});
});
I believe that is a sintax problem...But I'm yet noob in Jquery...
2007/10/25, Glen Lipka <[EMAIL PROTECTED]>:
>
> Can you post a simple page that demonstrates the problem?
> It's easier to debug that way.
>
> Glen
>
> On 10/25/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> >
> >
> > Hi there friends!!!
> >
> > I'm having problems with a code here using AJAX on Jquery.
> > When I do only one click in my object, it works fine, but, when I
> > click again in other object the previous result of id continue stored.
> >
> > What I have to do to solve this problem??
> >
> >
>
