Ae brazuca naum sei do resto mas sei que vc esta errando aqui
var id = $(this).attr("id_delete")
The attr method catch or set a the value of the jq object.
Try this
var id = $(this).attr("id")
On 10/25/07, Jimmy Neph <[EMAIL PROTECTED]> wrote:
> This is the code:
> $(".delete").click(function(e){
> var id = $(this).attr("id_delete")
> $("#confirm_box").css({left: e.pageX-453, top: e.pageY})
> $("#confirm_box").fadeIn(300);
> $("#del_nao").click(function(){
> $("#confirm_box").fadeOut(300);
> $(".delete").attr("id_delete","");
> });
> $("#del_sim").click(function(){
> alert(id);
> $("#del_sim").attr("id_user",id);
> $.ajax({
> type: "POST",
> url:"../painel/kern_usuarios.php",
> data:
> "id="+$(this).attr("id_user")+"&acao=del_user",
> success: function(msg){
> if(msg)
> {
> $("#confirm_box").fadeOut(300)
>
> $("#answer_box").text("Usuario deletado com
> sucesso");
> $("#answer_box").fadeIn(1000, function(){
> $(this).animate({opacity:1.0}, 1000, "",
> function(){
> $(this).fadeOut(1000, function(){
>
> $($("tr").attr("id_linha")).find("[EMAIL PROTECTED]"+id+"]").slideUp("slow");
> });
> });
> });
> }
> else
> {
> $("#confirm_box").fadeOut(300)
>
> $("#answer_box").text("Erro ao deletar
> usuario");
> $("#answer_box").fadeIn(300);
> }
> }
> });
> });
> });
>
>
> I believe that is a sintax problem...But I'm yet noob in Jquery...
>
> 2007/10/25, Glen Lipka < [EMAIL PROTECTED]>:
> > Can you post a simple page that demonstrates the problem?
> > It's easier to debug that way.
> >
> > Glen
> >
> >
> >
> > On 10/25/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> > >
> > > Hi there friends!!!
> > >
> > > I'm having problems with a code here using AJAX on Jquery.
> > > When I do only one click in my object, it works fine, but, when I
> > > click again in other object the previous result of id continue stored.
> > >
> > > What I have to do to solve this problem??
> > >
> > >
> >
> >
>
>
--
[]´s Jean
www.suissa.info
Ethereal Agency
www.etherealagency.com
