Hi, Karl.
No worries. I'm just impressed that someone as busy as you gets back
to us on these issues at all. Thank you!
Hm. Perhaps I wasn't clear on what I was trying to accomplish.
Probably either filter or find would be fine. What I'm looking for is
how to target the specific div on the ajax html page that matches the
class on the cluetips link. To be clear, I'd like to just have one
page of ajax info, rather than a different page for each cluetip
link. Then cluetip would just find the info that matches the link's
class.
This (copied from the code in my first post) works just fine: data=$
(data).filter('.tip_1');
But I would have to do that for each cluetip link on the page (and
there are several). What I need is this: data=$(data).filter('<some
variable that finds the matching div on the ajax page before
populating the cluetip>');
So
my_cluetip_page.html
ajax_info_page.html
-------------------------------
----------------------------
<a class="tips_1" rel="ajax.htm">Here's my cluetip link 1</a> --
> <div class="tips_1">Here's the cluetip info</div>
<a class="tips_1" rel="ajax.htm">Here's my cluetip link 2</a> --
> <div class="tips_2">Here's more cluetip info</div>
Does that make sense?
On Apr 1, 4:51 pm, Karl Swedberg <[EMAIL PROTECTED]> wrote:
> Hi Sterling,
>
> Sorry for taking so long to get back to you on this.
>
> It's tough for me to know which selector expression you should use
> without seeing the data that you're retrieving with the ajax call. I
> doubt that it's filter, though, unless it's a top-level element. You
> might want to try .find() instead.
>
> --Karl
> _________________
> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> On Mar 28, 2008, at 12:51 PM, SterlingK wrote:
>
>
>
>
>
> > First off, the hard work on cluetips. I'm a big fan and for a nub like
> > me, it's been remarkably easy to integrate and customize for my sites.
>
> > What I've been trying to do is have one html page that includes all
> > the ajax content in various divs (essentially like xml), like such:
> > <div class="tip_1">content here</div>
> > <div class="tip_2">more content here</div>
>
> > The tips would be able to filter according to matched class names. For
> > instance, the following would display the above information, filtered
> > by class name:
> > <a class="tips_1" rel="ajax.htm">Here's my cluetip link 1</a>
> > <a class="tips_2" rel="ajax.htm">Here's my cluetip link 2</a>
>
> > I can do it manually, like this:
> > ajaxProcess : function (data) {
> > data=$(data).filter('.tip_1');
> > return data;
> > }
>
> > But I'm having a hard time getting it to work dynamically. Using
> > something like 'data=$(data).filter(this.class) doesn't work. Again,
> > I'm pretty new at this and it seems like this should be fairly simple
> > to do with jquery, but I'm stuck after several hours of trying.
>
> > I saw the great demo that applies a similar concept at
> >http://test.learningjquery.com/clue/demo/danm.html, but have been
> > unable to combine what I need with that local example.
>
> > Many thanks in advance.
>
> > - Sterling- Hide quoted text -
>
> - Show quoted text -
