naa. i mean the bracket is wrong.
${'img').each(function(){
alert( $(this).width() );
});
you got 3 {
2 times you open the { and one time you close it }
and i guess it have to be $('img').each(...
you know what i mean?
On 29 Okt., 15:20, "Andy Matthews" <[EMAIL PROTECTED]> wrote:
> I meant to write img.
>
> All that's on the page are images. For every img on the page I was trying to
> alert it's width so that I could test it. To no avail though. It kept
> outputting as 0.
>
> Regarding the 404 suggestion, these are images not under my domain. I'm
> pulling in an image from a 3rd party website.
>
> andy
>
> -----Original Message-----
> From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On
>
> Behalf Of weidc
> Sent: Wednesday, October 29, 2008 9:15 AM
> To: jQuery (English)
> Subject: [jQuery] Re: Getting width of broken image?
>
> hi,
>
> eh.. did you copy your code? 'Cause you wrote {'img').
>
> On 29 Okt., 14:30, "Andy Matthews" <[EMAIL PROTECTED]> wrote:
> > I'm loading in a batch of images dynamically. Some of the images might
> > not exist and I'm wondering how I might test for that image using
> > jQuery (1.2.6). All I really want to do is to remove that img from the
> > DOM so that it doesn't show on the page.
>
> > I thought at first it would be simple enough to test the width of the
> image.
> > All the valid images should be around 600 pixels wide, whereas the
> > broken image should be 30 or so.
>
> > I tried this:
>
> > ${'img').each(function(){
> > alert( $(this).width() );
>
> > });
>
> > But I got 0 for both a valid, and invalid, image. Anyone have any ideas?
>
> > andy
