Hi again,

I tried that but got the same results.

if(res.result == '1') {
  $('form#submit').hide();
  $('div.success').fadeIn('medium');
} else {
  $('div.error').show();
}

if(res.result == 1) {
  $('form#submit').hide();
  $('div.success').fadeIn('medium');
} else {
  $('div.error').show();
}

res.result is always false even though firebug says the response is
{"result":1}.

Rob.



On Jan 4, 7:01 pm, donb <falconwatc...@comcast.net> wrote:
> On another thread, someone pointed out to me that json_encode was
> supposed to 'know' if the data values were numeric or string and only
> quote the latter.  That was not my experience, and perhaps not yours,
> either.  Try '1' as the value you compare to instead of 1.
>
> On Jan 4, 1:05 pm, rob303 <r...@cube33.com> wrote:
>
> > Interestingly, in the Firebug console I'm seeing the correct
> > responses:
>
> > {"result":1}
>
> > or
>
> > {"result":0}
>
> > How can I access these inside my $.ajax() call?
>
> > Many thanks again for all the help!
>
> > Rob.
>
> > On Jan 4, 5:57 pm, rob303 <r...@cube33.com> wrote:
>
> > > Yes, the missing semicolons are an error in the post. I tried to echo
> > > the json_encode() call but I still can't get it to work. If I leave
> > > the email input blank no email is sent. If I enter a string the email
> > > is sent. The 'div.error' is always displayed regardless what's posted.
>
> > > Here's my full code again:
>
> > > ------------------
> > > HTML / Ajax
> > > ------------------
> > > <?php
>
> > > require_once("../inc/site_config.php");
>
> > > require_once(SITE . "/includes.php");
> > > ?>
> > > <html>
> > >   <head>
> > >         <script src="js/jquery.js" type="text/javascript"></script>
> > >     <script type="text/javascript">
> > >       $(document).ready(function(){
> > >         $("form#submit").submit(function() {
> > >           var email = $('#email').attr('value');
> > >           $.ajax({
> > >             type: "POST",
> > >             url: "ajax.php?v=1",
> > >             data: "email="+ email,
> > >             success: function(res){
> > >               if(res.result == 1) {
> > >                 $('form#submit').hide();
> > >                 $('div.success').fadeIn('medium');
> > >               } else {
> > >                 $('div.error').show();
> > >               }
> > >             }
> > >           });
> > >           return false;
> > >         });
> > >       });
> > >     </script>
> > >   </head>
> > >   <body>
> > >       <form id="submit" method="post">
> > >         Email:
> > >         <input id="email" class="text" name="email" size="20"
> > > type="text" />
> > >             <input type="submit" value="send mail" />
> > >           </form>
> > >       <div class="success" style="display:none;">
> > >         Email sent.
> > >       </div>
> > >       <div class="error" style="display:none;">err</div>
> > >   </body>
> > > </html>
>
> > > --------------
> > > PHP
> > > --------------
> > > <?php
>
> > > require_once("includes.php");
>
> > > $message = $_POST['email'];
>
> > > if($message != '') {
> > >   mail('some-em...@email.com', 'Ajax test', $message);
> > >   $json_data = array('result' => 1);} else {
>
> > >   $json_data = array('result' => 0);
>
> > > }
>
> > > echo json_encode($json_data);
>
> > > ?>
> > > $message = $_POST['email'];
>
> > > if($message != '') {
> > >   mail('....@cube33.com', 'Ajax test', $message);
> > >   $json_data = array('result' => 1);} else {
>
> > >   $json_data = array('result' => 0);
>
> > > }
>
> > > echo json_encode($json_data);
>
> > > ?>
> > > --------------
> > > On Jan 4, 5:44 pm, donb <falconwatc...@comcast.net> wrote:
>
> > > > You must 'echo' the JSON output.  Also you indicate periods ending
> > > > code lines, instead of semicolons but perhaps that's just an error in
> > > > your post, not the actual code?
>
> > > > On Jan 4, 10:38 am, rob303 <r...@cube33.com> wrote:
>
> > > > > Hi,
>
> > > > > Many thanks for the help.  I had a go at implementing what you
> > > > > suggested but I'm clearly still missing something.
>
> > > > > Here is my $.ajax() call:
> > > > > ------------------
> > > > > $(document).ready(function(){
> > > > >         $("form#submit").submit(function() {
> > > > >           var email = $('#email').attr('value');
> > > > >           $.ajax({
> > > > >             type: "POST",
> > > > >             url: "ajax.php",
> > > > >             data: "email="+ email,
> > > > >             success: function(del){
> > > > >               if(del.result == 1) {
> > > > >                 $('form#submit').hide();
> > > > >                 $('div.success').fadeIn('medium');
> > > > >               } else {
> > > > >                 $('div.error').show();
> > > > >               }
> > > > >             }
> > > > >           });
> > > > >           return false;
> > > > >         });
> > > > >       });
> > > > > ------------------
>
> > > > > And here is my json array in PHP:
> > > > > ------------------
> > > > > $message = $_POST['email'];
>
> > > > > if($message != '') {
> > > > >   mail('some-em...@email.com', 'Ajax test', $message);
> > > > >   $json_data = array('result' => 1).} else {
>
> > > > >   $json_data = array('result' => 0, 'error' => 'This is an error').
>
> > > > > }
>
> > > > > json_encode($json_data);
> > > > > ------------------
>
> > > > > I'm obviously not accessing del.result correctly because $
> > > > > ('div.error').show(); is always executed regardless of the value of
> > > > > result.  Where am I going wrong?
>
> > > > > Thanks in advance,
>
> > > > > Rob.
>
> > > > > On Jan 4, 2:41 pm, donb <falconwatc...@comcast.net> wrote:
>
> > > > > > Return a JSON object.
>
> > > > > > Construct a PHP array such as $json_data = array('result' => 0,
> > > > > > 'error' => 'This is an error').  End your PHP script with 
> > > > > > json_encode
> > > > > > ($json_data).  Then you can reference del.result and del.error (I'm
> > > > > > referring to your definition of the' success' function from your
> > > > > > sample code)
>
> > > > > > On Jan 4, 7:16 am, rob303 <r...@cube33.com> wrote:
>
> > > > > > > Hi,
>
> > > > > > > I'm new to ajax and jquery but I'm not new to PHP.  The following
> > > > > > > example seems to work okay to a point but I can't figure out how 
> > > > > > > to
> > > > > > > handle data validation errors generated in my PHP.
>
> > > > > > > In my example I want to post some data to a script called 
> > > > > > > ajax.php.
> > > > > > > That script will check the data for validity and then return true 
> > > > > > > or
> > > > > > > false depending on the outcome of the checks. It will also set an
> > > > > > > appropriate error message.
>
> > > > > > > How can I handle the returned data and display an error message if
> > > > > > > needed in ajax?
>
> > > > > > > ----------------------
> > > > > > > HTML / Ajax - test.php
> > > > > > > ----------------------
> > > > > > > <?php
>
> > > > > > > require_once("includes.php");
>
> > > > > > > ?>
> > > > > > > <html>
> > > > > > >   <head>
> > > > > > >     <script src="js/jquery.js" type="text/javascript"></script>
> > > > > > >     <script type="text/javascript">
> > > > > > >       $(document).ready(function(){
> > > > > > >         $("form#submit").submit(function() {
> > > > > > >           var email = $('#email').attr('value');
> > > > > > >           $.ajax({
> > > > > > >             type: "POST",
> > > > > > >             url: "ajax.php",
> > > > > > >             data: "email="+ email,
> > > > > > >             success: function(del){
> > > > > > >               $('form#submit').hide();
> > > > > > >               $('div.success').fadeIn('medium');
> > > > > > >               // what if the data failed validation in PHP?
> > > > > > >               // we need to show 'div.error".
> > > > > > >             }
> > > > > > >           });
> > > > > > >           return false;
> > > > > > >         });
> > > > > > >       });
> > > > > > >     </script>
> > > > > > >   </head>
> > > > > > >   <body>
> > > > > > >     <form id="submit" method="post">
> > > > > > >       Email:
> > > > > > >       <input id="email" class="text" name="email" size="20"
> > > > > > > type="text" />
> > > > > > >       <input type="submit" value="send mail" />
> > > > > > >     </form>
> > > > > > >     <div class="success" style="display:none;">
> > > > > > >       Email sent.
> > > > > > >     </div>
> > > > > > >     <div class="error">
> > > > > > >       <?php echo $userError; ?>
> > > > > > >     </div>
> > > > > > >   </body>
> > > > > > > </html
>
> > > > > > > ----------------------
> > > > > > > PHP - ajax.php
> > > > > > > ----------------------
> > > > > > > <?php
>
> > > > > > > require_once("includes.php");
>
> > > > > > > $message = $_POST['email'];
>
> > > > > > > if($message != '') {
> > > > > > >   mail('some-em...@email.com', 'Ajax test', $message);
> > > > > > >   return 1;} else {
>
> > > > > > >   $userError = "Please enter your email address";
> > > > > > >   return 0;
>
> > > > > > > }
>
> > > > > > > ?>
>
> > > > > > > I've been searching the web for an answer but can't find one
> > > > > > > anywhere!  Any help would be greatly appreciated.

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