Ide ais to start excecution when ontents in loaded. So you should put only your ently point call there. Other functions/vars etc may be anywhere.
Best regards, Konstantin Mirin mailto:konstantin.mi...@gmail.com mailto:i...@konstantin.takeforce.net > -----Original Message----- > From: jquery-en@googlegroups.com > [mailto:jquery...@googlegroups.com] On Behalf Of 123gotoandplay > Sent: Saturday, February 07, 2009 1:39 PM > To: jQuery (English) > Subject: [jQuery] Re: How to enable jquery in a loaded page? > > > > hmm, so i need to put all the javascript, i have in > showContent.php's $ (document).ready(function () { > > in a callback function?? > > Can i leave the other js functions in showContent.php or > should i copy those function into my "base" php file?? > > regards, > > > > On 6 feb, 15:33, ilovejquery <ilovejqu...@gmail.com> wrote: > > It's probably because your jquery code is in $(document).ready() > > function and it is never fired when you load with .load(). > > > > Put your code in callback function like this: > > > > $(document).ready(function() { > > $("#show").click(function() { > > $("#content").css("overflow-y", "scroll"); > > $("#content").load("showContent.php", function(){ > > > > // your code here... > > > > }); > > > > }); > > > > ---- > > Read jQuery HowTo Resource - http://jquery-howto.blogspot.com > > > > On Fri, Feb 6, 2009 at 6:40 PM, 123gotoandplay > > <wesweatyous...@gmail.com> wrote: > > > > > Hi there, > > > > > I am having a problem to enable jquey in a loaded page. > > > > > For example: > > > > > base.php has jquery and i load showContent.php like: > > > > > $(document).ready(function() { > > > $("#show").click(function() { > > > $("#content").css("overflow-y", "scroll"); > > > $("#content").load("showContent.php"); > > > }); > > > > > but now the jquery in showContent.php doesn't work. > > > > > if i directly browse to showContent.php the jquery does work > > > > > Any tips?
