@Dreed, could you maybe be a little more specific about why you need
to do this in jQuery? A recursive function would be trivial (I can't
see how it's brute force) and you could make it generic such that
'tags' are created out of the classnames, no matter what they are.

On Mar 3, 3:53 pm, ricardobeat <ricardob...@gmail.com> wrote:
> Not showing your js function doesn't help much.
>
> All .group are descendants of .map, it's not about context.
>
> Maybe you want this (rough):
>
> $('.map').each(function(){
> var xml = '<map>';
> $(this).find('> .group').each(function(){
>    xml += '<group>';
>    $(this).find('> .group').each(function(){
>       xml += '<group>';
>       xml += $(this).text();
>       xml += '</group>';
>    });
>    xml += '</group>';
>
> });
> xml+= '</map>';
> });
>
> On Mar 3, 5:27 pm, DReed <danreed...@gmail.com> wrote:
>
> > I have been struggling with trying to do the following... perhaps I am
> > looking at it "too" hard since I have a feeling the solution is right
> > in front of me (i hope).
>
> > I have something like the following:
>
> > <div class="map">
> >    <div class="title">Title</div>
> >    <div class="group">
> >        Group Name 1
> >        <div class="group">Group Name 1-1</div>
> >    </div>
> >    <div class="group">
> >        Group Name 2
> >        <div class="group">Group Name 2-1</div>
> >    </div>
> > </div>
>
> > I would like to turn this into XML, like:
>
> > <map>
> >    <title>Title</title>
> >    <group>Group Name 1
> >       <group>Group Name 1-1</group>
> >    </group>
> >    <group>Group Name 2
> >       <group>Group Name 2-1</group>
> >    </group>
> > </map>
>
> > I have been trying using the .each() function but it doesn't seem to
> > hold the context node (when my context is the .map node and I want to
> > iterate the .group, it will iterate ALL of them, instead of the TWO
> > directly under the .map element.  I can brute force this with some
> > recursion but I thought there must be a way to retain the context of
> > the jQuery.
>
> > Perhaps the .each way isn't the right approach?
>
> > Thanks in advance.

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