I simplified my code and remove $("a) code too..
function updateNav(param) {
$.ajax({
type: "POST",
cache: false,
url: "assets/ajax/updatenav.php",
data: "opt="+param,
success: function(d){
$("#nav").html(d);
}
});
}
and...
<ul id="nav">
<li class="disabled">HOME</li>
<li class="active"><a href="javascript:updateNav('menu');"
class="menu">MENU</a></li>
<li class="active"><a href="javascript:updateNav('catering');"
class="catering">CATERING</a></li>
<li class="active"><a href="javascript:updateNav('contact');"
class="contact">CONTACT</a></li>
</ul>
... and that worked. So how can I use jQuery to repeat my ajax call
(s)?
On Mar 15, 10:04 pm, "so.phis.ti.kat" <see.marlon....@gmail.com>
wrote:
> Question.
>
> I have it working right now but i can't get it to work more than
> once.
> I am using $.ajax(); and $("a").click(); to initiate this.
>
> 5 menu buttons, the first one always works, no matter which one, but
> after it refreshes, the other buttons don't work.
>
> I am wondering if it is because I am using jQuery to enable my
> clicks?
>
> On Mar 13, 1:23 pm, "so.phis.ti.kat" <see.marlon....@gmail.com> wrote:
>
> > Thanks Guys.
> > I'll have a look now.
>
> > On Mar 11, 1:31 pm, Paul Hutson <hutsonphu...@googlemail.com> wrote:
>
> > > > > Ajax.Updater allows you to simply update the content of a DIV.
>
> > > If you want to go back to the super simple, you can update the inner
> > > content of a div with:
>
> > > $("#DIVID").html("CONTENT");
>
> > > i.e. :
> > > <div id="blah"></div>
>
> > > <script>
> > > $("#blah").html("I've just been added to the div blah...");
> > > </script>
>
> > > Therefore, on your callback from the AJAX - as mkmanning has posted -
> > > you could do the update using the items that come back from the ajax.
>
> > > Regards,
> > > Paul
