Dave Methvin showed someone else another way to do this back in
December. Here is a slightly modified version of his approach:
$(document).ready(function() {
var $divs = $('div').hide(),
div = 0;
(function(){
$divs.eq(div++).show('slow', arguments.callee);
})();
});
--Karl
____________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Mar 16, 2009, at 10:23 PM, Tom Shafer wrote:
im getting too much recursion in firebug, any thought?
On Mar 16, 7:26 pm, ricardobeat <ricardob...@gmail.com> wrote:
jQuery.fn.showLoop = function(i){
var i = i || 0,
self = this;
$( this[i] ).show(600, function(){
self.showLoop(++i);
});
};
$('.type').showLoop();
On Mar 16, 7:27 pm, Tom Shafer <tom.sha...@gmail.com> wrote:
how can i loop through each div on a page and have them appear one
by
one
i am trying
var arrayList2 = $.makeArray(document.getElementsByClassName
(".type"));
$.each(arrayList2,function() {
$
(this).show();
});
thanks
-tj