The problem here appears to be the change jQuery made with 1.3.2 with how it determines visibility.
http://jsbin.com/omavi/edit That link is a quick demonstration of how it works. A "visible" object to jquery is determined by if it takes up space in the page, and has nothing to do with the css property "visibility". This is pretty deceiving, and I'm not sure why they decided to do it that way, but it breaks down like this: A visible element one, even ones with or visibility:hidden" and "position: absolute; left: -9999px" will return with the :visibility selector An element which does not take up space, such as one with "display:none" will not return with the :visibility selector. Now, in your code, you reference $j('selector'). I'm not at all familiar with $j as a way to interface with jQuery. But there is proof it works, and as expected (at least to what jQuery says). On Mar 17, 8:36 pm, Andy789 <e...@abcstudio.com.au> wrote: > No, just to make it real simple: > > function test(){ > var vis = $j('li.jqtip:visible').length; > alert(vis); //correct alert OK, returns some number here! > $j('li.jqtip:visible').each(function() > { alert('something here'); //nothing happens !!! > > }) > } > > All alerts inside .each(function.... do not work. > > Any ideas? > > On Mar 18, 7:18 am, James <james.gp....@gmail.com> wrote: > > > What happens if you remove the code for the qtip and leave the alert? > > > On Mar 17, 10:14 am, Andy789 <e...@abcstudio.com.au> wrote: > > > > Yes, this is what i was doing, but puzzled as why the second alert > > > never triggers: > > > >functiontips(){ > > > alert($j('li.jqtip:visible').length); //returns 9 > > > $j('li.jqtip:visible').each(function() > > > { alert('something here'); //returns nothing, but thefunctionis > > > working and creates tooltips !!!!!! > > > $j(this).qtip({ .............. > > > > How is that possible? > > > > On Mar 18, 12:28 am, MorningZ <morni...@gmail.com> wrote: > > > > > First, it would be wise to see what your selector returns > > > > > functiontips(){ > > > > alert($j('li.jqtip:visible').length); > > > > > } > > > > > if that returns "0", then your selector is wrong > > > > > to help with that, there was this excellent post about breaking > > > > changes in 1.3.2 release, in your case reading the ":visible" section > > > > would probably be of great help > > > > >http://www.learningjquery.com/2009/03/3-quick-steps-for-a-painless-up... > > > > > Andy789 wrote: > > > > > Hi All, > > > > > > Here is a simplefunction- works fine, but I cannot get alerts for > > > > > debugging - no errors - no alerts: > > > > > >functiontips(){ > > > > > > $j('li.jqtip:visible').each(function() > > > > > { alert('something here'); //this alert is not working !!!!!! > > > > > $j(this).qtip({ > > > > > content: $j(this).attr('title'), > > > > > show: { effect: 'grow', length: 400 }, > > > > > hide: { effect: 'grow', length: 400 }, > > > > > position: { > > > > > corner: { > > > > > target: 'topMiddle', > > > > > tooltip: 'bottomLeft' > > > > > } > > > > > }, > > > > > style: { > > > > > tip: 'bottomLeft', > > > > > name: 'dark', > > > > > border: { > > > > > width: 2, > > > > > radius: 8 > > > > > //color: '#666666' > > > > > }, > > > > > width: 200 > > > > > } > > > > > }); > > > > > }); > > > > > } > > > > > > What is wrong here? I feel it is something very obvious...
