Hello Michael, thanks for this. I got a error: > html.find is not a function Any idea?
<script type='text/javascript' src='http://ajax.googleapis.com/ajax/ libs/jquery/1.3.2/jquery.min.js'></script> <script type="text/javascript"> $(document).ready(function(){ $.ajax({ url: "leistung.html", cache: false, success: function(html) { var loadCont = html.find('#cont'); $(".content").append(loadCont); } }); }); </script> On Apr 27, 5:07 pm, Michael Lawson <mjlaw...@us.ibm.com> wrote: > instead of $(".content").append(html); > do > var contentToAppend = html.find("#cont"); > $(".content").append(contentToAppend); > > cheers > > Michael Lawson > Content Tools Developer, Global Solutions, ibm.com > Phone: 1-828-355-5544 > E-mail: mjlaw...@us.ibm.com > > 'Examine my teachings critically, as a gold assayer would test gold. If you > find they make sense, conform to your experience, and don't harm yourself > or others, only then should you accept them.' > > From: "clicforw...@googlemail.com" <clicforw...@googlemail.com> > > > To: "jQuery (English)" <jquery-en@googlegroups.com> > > > Date: 04/27/2009 11:03 AM > > > Subject: [jQuery] ajax append problem > > > Hello, > > im using this script to load a external site into my DOM. > It works fine but i need just a part of this test.html. > > For example: I want to append just the div "#cont" from test.html > How can i do that? > > <script type="text/javascript"> > $.ajax({ > url: "test.html", > cache: false, > success: function(html){ > $(".content").append(html); > }}); > > </script> > > Thanks for Help! > > graycol.gif > < 1KViewDownload > > ecblank.gif > < 1KViewDownload
