When i try this i get an error "object required" in IE6 and 7. any
thoughts?

On Apr 27, 10:10 pm, Ricardo <ricardob...@gmail.com> wrote:
> I think you have to separate the selector otherwise it's just a hash:
>
> $(".content").load("test.html #content");
>
> http://docs.jquery.com/Ajax/load
>
> On Apr 27, 5:14 pm, Charlie <charlie...@gmail.com> wrote:
>
> > $(".content").load("test.html#content");
> > this will grab only theidcontent from test.html andloadit , can refine this 
> > down to elements within #content as well
> > example on jQuery site shows same 
> > methodclicforw...@googlemail.comwrote:Hello Michael, thanks for this. I got 
> > a error: > html.find is not a function Any idea? <script 
> > type='text/javascript' 
> > src='http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js'></script>
> >  <script type="text/javascript"> $(document).ready(function(){ $.ajax({ 
> > url: "leistung.html", cache: false, success: function(html) { var loadCont 
> > = html.find('#cont'); $(".content").append(loadCont); } }); }); </script> 
> > On Apr 27, 5:07 pm, Michael Lawson<mjlaw...@us.ibm.com>wrote:instead of  
> > $(".content").append(html); do var contentToAppend = html.find("#cont"); 
> > $(".content").append(contentToAppend); cheers Michael Lawson Content Tools 
> > Developer, Global Solutions, ibm.com Phone:  1-828-355-5544 E-mail:  
> > mjlaw...@us.ibm.com'Examine my teachings critically, as a gold assayer 
> > would test gold. If you find they make sense, conform to your experience, 
> > and don't harm yourself or others, only then should you accept them.'   
> > From:      "clicforw...@googlemail.com"<clicforw...@googlemail.com>         
> >                                                    To:         "jQuery 
> > (English)"<jquery-en@googlegroups.com>                                      
> >                                 Date:       04/27/2009 11:03 AM             
> >                                                                             
> >           Subject:    [jQuery]ajaxappend problem                            
> >                                                              Hello, im 
> > using this script toloada external site into my DOM. It works fine but i 
> > need just a part of this test.html. For example: I want to append just the 
> > div "#cont" from test.html How can i do that? <script 
> > type="text/javascript"> $.ajax({   url: "test.html",   cache: false,   
> > success: function(html){     $(".content").append(html);   }}); </script> 
> > Thanks for Help!  graycol.gif < 1KViewDownload  ecblank.gif < 1KViewDownload

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