Its simple.
Just remove the $.post function then do this:
$(this).ajaxSubmit({
type: 'post',
url: '/update',
* data: queryString,*
target: '#userForm',
success: function()
{alert(queryString);}
});
return false; // <-- important!
2009/6/2 Dave Maharaj :: WidePixels.com <d...@widepixels.com>
>
> Can someone give me a hand getting this right. Using the jQuery Form Plugin
> on http://malsup.com/jquery/form/ I am trying to submit a form but the
> script I am having problems with. I know its wrong...but cant figure out
> how
> to remove the duplicate post and url parts.
>
> $(document).ready(function() {
> $('#UpdateForm').bind('submit', function() {
> var queryString = $('#UpdateForm').formSerialize();
> $.post('/update', queryString);
> $(this).ajaxSubmit({
> type: 'post',
> url: '/update',
> target: '#userForm',
> success: function()
> {alert(queryString);}
> });
> return false; // <-- important!
> });
> });
>
> Can someone point out the correct way to set up this function?
>
> Thanks,
>
> Dave
>
>
--
Gustavo Salome Silva
