I resolved my problem using callback. I put the second load in the callback function of first one. Thanks for your answer.
2009/12/4 Michel Belleville <michel.bellevi...@gmail.com> > Well it depends ; most of the times you end up loading a big bit of data > that should replace a specific portion of the screen (let the standard > .load() behaviour do the heavy lifting for this one) plus a few tidbits like > notifications and so on that are secondary (can be dealt with in the > callback), so your code is just a little bit more expressive (the "main" > purpose of the query is expressed first in the .load() mandatory parameters, > then the "secondary" tidbits are placed later in the callback). Using .get() > would also do the job, but would be slightly less readable later. > > Michel Belleville > > > 2009/12/4 Richard D. Worth <rdwo...@gmail.com> > > I think you're better of with $.get and then doing the finding and loading >> into both divs yourself. >> >> - Richard >> >> >> On Fri, Dec 4, 2009 at 5:21 AM, NMarcu <marcu.nico...@gmail.com> wrote: >> >>> Hi, >>> >>> I need to update a div that contain a table, and another one that >>> contain a drop down list, that is build depending on what is in one >>> table from db(the first div depend on this also). It's possible to >>> update the 2 divs with the same load, or need to use two load. I try >>> this but not worked correct. >>> >>> Thanks. >>> >> >> > -- All the best, Nicolae MARCU
