Sorry, misunderstood.
I wasn't clear on what you were trying to do, but saw the "Maybe I'm not
understanding the point of .add()", so was trying to clarify that.
Glad MorningZ got you sorted :)
On Wed, Dec 23, 2009 at 10:59 AM, Scott <polyp...@gmail.com> wrote:
> Uh, that's not what I'm asking at all.
>
> In the documentation example you're passing .add() the "p" selector
> which is a string. I want the end result to be the same except instead
> of passing a selector string like "p" I want to pass an existing
> jquery object. It doesn't seem to work this way and the only time more
> elements get added to to jquery object is if you use a selector.
>
> Sso I want to do more like :
> $("div").css("border", "2px solid red")
> .add($(this).children()) //see how this line is different
> .css("background", "yellow");
>
>
> On Dec 23, 12:50 pm, Charlie Griefer <charlie.grie...@gmail.com>
> wrote:
> > As per the docs (http://docs.jquery.com/Traversing/add),
> >
> > $("div").css("border", "2px solid red")
> > .add("p")
> > .css("background", "yellow");
> >
> > That will add a 2px red border around any 'div' element.
> >
> > Then add in a new selector and grab all of the <p> elements. Add a
> yellow
> > background to the previously selected <div> elements, as well as the
> newly
> > selected <p> elements.
> >
> > Does that clarify add()?
> >
> > I'm not sure I understand what it is you're trying to accomplish. Can
> you
> > explain what you need to do?
> >
> >
> >
> > On Wed, Dec 23, 2009 at 10:45 AM, Scott <polyp...@gmail.com> wrote:
> > > Maybe I'm not understanding the point of .add() but it doesn't really
> > > do what I'd expect nor can I figure out how to do what I thought would
> > > be simple.
> >
> > > I want to combine 2 jquery objects.
> >
> > > var $obj1 = $(".stuff");
> > > var $obj2 = $(".morestuff");
> > > $obj1.add($obj2);
> > > alert($obj1.length);
> >
> > > This doesn't do anything, it looks like .add() only accepts selection
> > > strings which in my example would work but in what I really need to do
> > > I have no selection string which would find the specific jquery
> > > objects.
> >
> > --
> > Charlie Grieferhttp://charlie.griefer.com/
> >
> > I have failed as much as I have succeeded. But I love my life. I love my
> > wife. And I wish you my kind of success.
>
--
Charlie Griefer
http://charlie.griefer.com/
I have failed as much as I have succeeded. But I love my life. I love my
wife. And I wish you my kind of success.
